"""
Auther:少校
Time:2025/3/31 16:54
越努力，越幸运
"""
# 1. 合并两个字典
dict1={1:1,2:2}
dict2={3:3,4:4}
for x in dict2:
dict1[x] =dict2[x]
print(dict1)
# 2. 遍历字典的键和值
dict1={'name': '酸奶', 'price': 3, 'count': 18, 'discount': 0.95}
print({(x , dict1[x]) for x in dict1})
# 3. 检查键是否存在于字典中
if "张三" not in dict1:
print("张三不在dict1")
else:
print("张三在dict1")
# 4. 获取字典所有键组成的列表
print([x for x in dict1])
# 5. 获取字典所有值组成的列表
print([dict1[x] for x in dict1])
# 6. 将两个列表合并为字典
list1 = ['name', 'age', 'score', 'gender']
list2 = ['张三', 19, 99, '男']
# 结果: {'name': '张三', 'age': 19, 'score': 99, 'gender':'男'}
dict1={list1[x]:list2[x] for x in range(len(list1))}
print(dict1)
# 7.字典键值互换
print({dict1[x]:x for x in dict1})
# 8.统计字典中值的数据类型分布
dict1={'name': '酸奶', 'price': 3, 'count': 18, 'discount': 0.95}
dict2={}
for x in dict1:
if type(dict1[x]) not in dict2:
dict2[type(dict1[x])]=1
else:
dict2[type(dict1[x])]+=1
print(dict2)
# 9.统计字符串中各字符出现次数
str1="pythonpppppyythooon"
print({x: str1.count(x) for x in str1})
# 10. 已知一个变量保存图书馆所有图书的信息（每一本书包括：书名、作者、类别、是否已经借出、借出时间、借书人）。
# 然后完成下面的题目：
books = [
{
"书籍名称": "Python编程：从入门到实践",
"作者": "Eric Matthes",
"类别": "计算机科学",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "流畅的Python",
"作者": "Luciano Ramalho",
"类别": "计算机科学",
"是否已经借出": True,
"借出时间": '2025-2-18',
"借书人": {'name': '小明', '学号': '100929292'}
},
{
"书籍名称": "百年孤独",
"作者": "加西亚·马尔克斯",
"类别": "文学",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "人类简史",
"作者": "尤瓦尔·赫拉利",
"类别": "历史",
"是否已经借出": True,
"借出时间": '2024-6-5',
"借书人": {'name': '小花', '学号': '9283839393'}
},
{
"书籍名称": "白夜行",
"作者": "东野圭吾",
"类别": "小说",
"是否已经借出": True,
"借出时间": '2024-3-20',
"借书人": {'name': '张三', '学号': '2389092221'}
},
{
"书籍名称": "三体",
"作者": "刘慈欣",
"类别": "文学",
"是否已经借出": True,
"借出时间": '2024-12-5',
"借书人": {'name': '李四', '学号': '00009282833'}
},
{
"书籍名称": "深度学习入门",
"作者": "斋藤康毅",
"类别": "人工智能",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "追风筝的人",
"作者": "卡勒德·胡赛尼",
"类别": "文学",
"是否已经借出": True,
"借出时间": '2025-3-18',
"借书人": {'name': '何丹', '学号': '01299923'}
},
{
"书籍名称": "算法图解",
"作者": "Aditya Bhargava",
"类别": "计算机科学",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "活着",
"作者": "余华",
"类别": "文学",
"是否已经借出": True,
"借出时间": '2025-3-20',
"借书人": {'name': '赵桂珍', '学号': '01029222'}
},
{
"书籍名称": "时间简史",
"作者": "史蒂芬·霍金",
"类别": "科普",
"是否已经借出": True,
"借出时间": '2024-11-22',
"借书人": {'name': '刘小龙', '学号': '10209292'}
},
{
"书籍名称": "围城",
"作者": "钱钟书",
"类别": "文学",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "Effective Python",
"作者": "Brett Slatkin",
"类别": "计算机科学",
"是否已经借出": True,
"借出时间": '2025-2-28',
"借书人": {'name': '赵桂珍', '学号': '01029222'}
},
{
"书籍名称": "挪威的森林",
"作者": "村上春树",
"类别": "文学",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "数据结构与算法分析",
"作者": "Mark Allen Weiss",
"类别": "计算机科学",
"是否已经借出": True,
"借出时间": '2024-6-5',
"借书人": {'name': '小花', '学号': '9283839393'}
},
{
"书籍名称": "机器学习实战",
"作者": "Peter Harrington",
"类别": "人工智能",
"是否已经借出": False,
"借出时间": None,
"借书人": None
},
{
"书籍名称": "平凡的世界",
"作者": "路遥",
"类别": "小说",
"是否已经借出": True,
"借出时间": '2025-3-15',
"借书人": {'name': '小花', '学号': '9283839393'}
}
]
# 1）打印所有的书名
print([x["书籍名称"] for x in books])
# 2）获取所有"计算机"类别的书名
print([x["书籍名称"] for x in books if x["类别"]=="计算机科学"])
# 3）统计不同类别的书籍的数量
dict1={}
# for x in books:
# if x["类别"] not in dict1:
# dict1[x["类别"]] = 1
# else:
# dict1[x["类别"]] += 1
# print(dict1)
for x in books:
t = x["类别"]
dict1[t] = dict1.get(t,0) +1
print(dict1)
# 4) 获取借书的数量超过一本的学生的信息
# jie={}
# for x in books:
# if x["借书人"] != None:
# if x["借书人"]['name'] not in jie:
# jie[x["借书人"]['name']] =1
# else:
# jie[x["借书人"]['name']] += 1
# print(jie)
# dict2=[]
# for x in jie:
# if jie[x] >1 :
# for y in books:
# if y["借书人"] != None:
# if y["借书人"]['name']== x and y["借书人"] not in dict2:
# dict2.append(y["借书人"])
# print(dict2)
jie=[]
for x in books:
if x["借书人"] is not None:
jie.append(x["借书人"])
jie2=[]
for x in jie:
if jie.count(x) > 1 and x not in jie2:
jie2.append(x)
print(jie2)
# 5）统计已经超时的图书的名字和对应的借书人学号(借出一个月没有还就算超时) -- 涉及python时间操作，可以不做
from datetime import datetime
for x in books:
if x["借出时间"] is not None and (datetime.now() - datetime.strptime(x["借出时间"], "%Y-%m-%d")).days > 30:
print(x["书籍名称"],x["借书人"]['学号'])05.homework
本节6168字2025-04-01 10:48:45
