""" Auther:少校 Time:2025/4/8 17:21 越努力,越幸运 """ from random import choices # 1.编写一个函数,接收两个数字参数并返回它们的和 def sx_sum(num1,num2): return num1 + num2 sum3=sx_sum(10,20) print(sum3) # 2.写一个函数计算圆的面积 def circle(radius:int): return 3.14 * radius**2 circle1=circle(5) print(circle1) # 3.创建一个函数,判断一个数是否为偶数 def is_ou(num1:int): if num1 % 2 == 0: return "是偶数" else: return "是奇数" print(is_ou(3)) # 4.编写函数将摄氏度转换为华氏度 def she_hua(du): return du * (9 / 5) + 32 zhuan=she_hua(10) print(zhuan) # 5.实现函数统计字符串中元音字母(a, e, i, o, u)的数量 def yuan_count(str1:str): count1= 0 for x in str1: if x in "aeiouAEIOU": count1 += 1 return count1 yuan_count1=yuan_count("abcedupoiqwe") print(yuan_count1) # 6.创建函数检查字符串是否为回文(正反相同) def is_hui(str1): if str1 == str1[::-1]: return "是回文" else: return "不是回文" print(is_hui("abcba")) # 7.编写函数返回列表中最大值(不使用内置函数) def is_max(list1:list): max1 = 0 for x in list1: if x > max1: max1 = x return max1 print(is_max([1,2,3,4,99,8])) # 8.写一个函数生成指定长度的随机密码(包含大小写字母和数字) def passwd(num1:int): from random import randrange str1="" for x in range(num1): a = chr(randrange(48, 57)) b = chr(randrange(65, 90)) c = chr(randrange(97, 122)) if randrange(0,2) == 0: str1 += a elif randrange(0,2) == 1: str1 += b else: str1 += c return str1 print(passwd(8)) #方法二: def random_password(num1:int): all_list=[chr(x) for x in range(97,97+26)] + [chr(x) for x in range(65,65+26)] + [str(x) for x in range(10)] return "".join(choices(all_list,k=num1)) print(random_password(9)) # 9.创建函数合并两个列表并去重 def hb_list(list1,list2): list3 = list1 + list2 list4 = [] for x in list3: if x not in list4: list4.append(x) return list4 print(hb_list([1,2,3,4,5,6,7,7],[6,7,7,8,9,5,4,3])) # 10.实现函数计算任意多个数字的平均值 def pjz(*nums): return sum(nums) / len(nums) print(pjz(1,2,3,4,5,6,7,8,9)) # 11.创建函数检查参数是否为质数 def is_zhi(num:int): for x in range(2,num): if num % x == 0: return "不是质数" return "是质数" print(is_zhi(4)) # 12.创建函数验证密码强度(长度、大小写、特殊字符) def is_q(str1:str): from re import findall if findall(r"[a-z]",str1) is not None and findall(r"[A-Z]",str1)is not None and findall(r"[\W_]",str1) is not None and len(str1) >= 8: return "密码强度很高" else: return "密码强度不够" print(is_q("ad*A6d2a0")) #方法二 def password_strength(pw:str): """ 验证密码强度 强度标准:长度超过6位,同时包含大小写和特殊字符(,.?~@$^&*!) :param pw: :return: """ if len(pw) <=6: return "弱" c1 = c2 = c3 = 0 for x in pw: if x.islower(): c1 += 1 elif x.isupper(): c2 += 1 elif x in ",.?~@$^&*!": c3 += 1 if c1 > 0 and c2 > 0 and c3 > 0: return "强" return "弱" print(password_strength("ad*A6d2a0"))
13.homework
本节2822字2025-04-09 16:46:56